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HRID2215401

反应详情

EQUATION

反应方程式

HRID 2215401 的结构方程式

REACTANTS

反应物

2
结构：COc1ccc(F)cc1C(C)(C)CC(O)(C=O)C(F)(F)F
HCID11573122

未命名化合物

结构：CC(=O)Nc1ccc2c(N)cccc2n1
HCID21948829

未命名化合物

PRODUCTS

生成物

1
结构：COc1ccc(F)cc1C(C)(C)CC(O)(CNc1cccc2nc(NC(C)=O)ccc12)C(F)(F)F
HCID21948871

未命名化合物

收率 46.4%

PROCEDURE

实验过程

Analogously to Example 20, 263 mg (0.86 mmol) of 4-(5-fluoro-2-methoxyphenyl)-2-hydroxy-4-methyl-2-(trifluoromethyl)pentanal and 205 mg (1.0 mmol) of 2-acetylamino-5-aminoquinoline are reacted to form 197 mg of product.