p-Fluoronitrobenzene → HCID 23725481, compound

HRID 2219340Notes

Reaction equation

HRID 2219340 reaction equation
[F:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[C:12]([C:13]3[N:14]=[CH:15][NH:16][CH:17]=3)=[C:11]([CH3:18])[O:10][N:9]=2)=[CH:4][CH:3]=1.F[C:20]1[CH:25]=[CH:24][C:23]([N+:26]([O-:28])=[O:27])=[CH:22][CH:21]=1>>[F:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[C:12]([C:13]3[N:14]=[CH:15][N:16]([C:20]4[CH:25]=[CH:24][C:23]([N+:26]([O-:28])=[O:27])=[CH:22][CH:21]=4)[CH:17]=3)=[C:11]([CH3:18])[O:10][N:9]=2)=[CH:4][CH:3]=1

Participants

3

Reactant 2

HCID 9590p-FluoronitrobenzeneHCID 178434995HCID 178434995, compound

Product 1

HCID 23725481HCID 23725481, compoundYield 72%

Procedure

As described for Example 46, 3-(4-fluoro-phenyl)-4-(1H-imidazol-4-yl)-5-methyl-isoxazole (97 mg, 0.4 mmol) using 1-fluoro-4-nitrobenzene instead of 4-fluoroacetophenone was converted to the title compound (105 mg, 72%) which was obtained as a light yellow solid. MS: m/e=365.1 [M+H]+.

Sources & evidence

ORD record
ord-e0f4e584e1be4437828cb215bb9b93a6
Source dataset
uspto-grants-2008_08
Patent number
US07414061B2

Reaction notes

Loading…