p-Fluoronitrobenzene → HCID 23725482, compound

HRID 2219342Notes

Reaction equation

HRID 2219342 reaction equation
[Br:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[C:12]([C:13]3[N:14]=[CH:15][NH:16][CH:17]=3)=[C:11]([CH3:18])[O:10][N:9]=2)=[CH:4][CH:3]=1.F[C:20]1[CH:25]=[CH:24][C:23]([N+:26]([O-:28])=[O:27])=[CH:22][CH:21]=1>>[Br:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[C:12]([C:13]3[N:14]=[CH:15][N:16]([C:20]4[CH:25]=[CH:24][C:23]([N+:26]([O-:28])=[O:27])=[CH:22][CH:21]=4)[CH:17]=3)=[C:11]([CH3:18])[O:10][N:9]=2)=[CH:4][CH:3]=1

Participants

3

Reactant 2

HCID 9590p-FluoronitrobenzeneHCID 178434973HCID 178434973, compound

Product 1

HCID 23725482HCID 23725482, compoundYield 92%

Procedure

As described for Example 49, 3-(4-bromo-phenyl)-4-(1H-imidazol-4-yl)-5-methyl-isoxazole (91 mg, 0.3 mmol) using 1-fluoro-4-nitrobenzene instead of 4-fluoroacetophenone was converted to the title compound (117 mg, 92%) which was obtained as a light yellow solid. MS: m/e 425.0/426.9 [M+H]+.

Sources & evidence

ORD record
ord-90cfe565c6a241839f2a6ccba7d43cba
Source dataset
uspto-grants-2008_08
Patent number
US07414061B2

Reaction notes

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