3-(3-Methylphenoxy)propan-1-ol → 3-(3-methylphenoxy)propanoic acid
Reaction equation
[CH3:1][C:2]1[CH:3]=[C:4]([CH:10]=[CH:11][CH:12]=1)[O:5][CH2:6][CH2:7][CH2:8][OH:9].CC(C)=[O:15].OS(O)(=O)=O.O=[Cr](=O)=O>CC(C)=O>[CH3:1][C:2]1[CH:3]=[C:4]([CH:10]=[CH:11][CH:12]=1)[O:5][CH2:6][CH2:7][C:8]([OH:15])=[O:9]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
This compound was prepared in a manner analogous to that of Step C of Example 2, by the reaction of 2.0 grams (0.012 mole) of 3-(3-methylphenoxy)propan-1-ol and 10 mL of Jones Reagent in 30 mL of acetone. The yield of subject compound was 1.5 grams. The NMR spectrum was consistent with the proposed structure.
Workup
- customThis compound was prepared in a manner analogous to that of Step C of Example 2
Sources & evidence
- ORD record
- ord-255dbc5a2f4a4573a4184c9bbf32d9a6
- Source dataset
- uspto-grants-2008_08
- Patent number
- US07417057B2
Reaction notes
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