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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 22224Generated: October 26, 2026

Sodium borohydride → N-(2-chloro-5-pyridylmethyl)2-aminoethanethiol

https://huagongshe.com/reaction/22224

Reaction equation

Participants

RoleNameHCIDCharge
ReactantSodium borohydrideHCID 4311764—
Reactant2-(2-Chloro-5-pyridyl)thiazolidineHCID 13752789—
SolventEthanolHCID 702—
ProductN-(2-chloro-5-pyridylmethyl)2-aminoethanethiolHCID 1375279082.2%

Reaction Steps

A solution composed of 6-chloronicotinaldehyde (14.2 g), 2-aminoethanethiol (7.7 g) and benzene (80 ml) was heated with stirring for 5 hours while removing water as an azeotrope. After the reaction, benzene was distilled off under reduced pressure, and further volatile materials were removed at 1 mmHg and 70° C. to give 2-(2-chloro-5-pyridyl)thiazolidine (18 g) as a residue. Ten grams of 2-(2-chloro-5-pyridyl)thiazolidine was dissolved in 100 ml of ethanol, and sodium borohydride was added. With stirring, the mixture was gradually heated and thereafter refluxed for 1 hour. Ethanol was distilled off under reduced pressure, and chloroform was added to the residue. Insoluble materials were separated by filtration and the chloroform layer was washed with water and dehydrated. Chloroform was distilled off under reduced pressure to give the desired N-(2-chloro-5-pyridylmethyl)2-aminoethanethiol (8.3 g).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05428032
Source datasetuspto-grants-1995_06
ORD IDord-fc8c385ebf3f48ea83cbfd1bc152ed16
Source noteuspto-grants-1995_06