HRID2224303

反应详情

EQUATION

反应方程式

HRID 2224303 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

2

PROCEDURE

实验过程

To a solution of compound 2B (13.6 mg, 0.036 mmol) in MeOH (5 mL) was added 10% Pd/C (3 mg) and the mixture was stirred under a balloon filled with hydrogen for 1 hour. The reaction was filtered through a 0.45 micron filter membrane and concentrated in vacuo to give the title compound (13.6 mg, 100%). HPLC Rt=2.996 min. (Column: YMC ODS-A 4.6×50 mm (4 min.); Solvent A=10% MeOH, 90% H2O, 0.1% TFA; Solvent B=90% MeOH, 10% H2O, 0.1% TFA); LCMS Found: (M+H)+=378.

WORKUP

后处理

  1. filtrationThe reaction was filtered through a 0.45 micron
  2. filtrationfilter membrane
  3. concentrationconcentrated in vacuo