HRID2224343

反应详情

EQUATION

反应方程式

HRID 2224343 的结构方程式

PROCEDURE

实验过程

The title compound (70.6 mg, 54%) was prepared from 6C (80 mg, 0.41 mmol) and 41B (80 mg, 0.41 mmol) in two steps by a route analogous to that used for the preparation of 1D. HPLC Rt=2.782 min; LCMS Found: (M+H)+=319.