(4-Aminophenoxy)benzene → HCID 7923047, compound

HRID 222859Notes

Reaction equation

HRID 222859 reaction equation
F[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=1[N+:8]([O-:10])=[O:9].[O:11]([C:18]1[CH:24]=[CH:23][C:21]([NH2:22])=[CH:20][CH:19]=1)[C:12]1[CH:17]=[CH:16][CH:15]=[CH:14][CH:13]=1.C([O-])(C)(C)C.[K+]>CS(C)=O>[N+:8]([C:3]1[CH:4]=[CH:5][CH:6]=[CH:7][C:2]=1[NH:22][C:21]1[CH:20]=[CH:19][C:18]([O:11][C:12]2[CH:17]=[CH:16][CH:15]=[CH:14][CH:13]=2)=[CH:24][CH:23]=1)([O-:10])=[O:9]

Participants

5

Reactant 3

HCID 8764(4-Aminophenoxy)benzeneHCID 738951-Fluoro-2-nitrobenzeneHCID 23665647Potassium tert-butoxide

Product 1

HCID 7923047HCID 7923047, compound

Reagents, catalysts & solvents 1

HCID 679Dimethyl SulfoxideSolvent

Procedure

The product (2.03 g) is obtained according to the method of stage 1 of Example 4, by using 3.7 mL of 2-fluoro-nitrobenzene and 7.88 g of 4-phenoxyaniline in the presence of 6.36 g of potassium tert-butanolate in 34 mL of DMSO.

Sources & evidence

ORD record
ord-15bf870785134774a9d8416a0ffb29ad
Source dataset
uspto-grants-2012_06
Patent number
US08207373B2

Reaction notes

Loading…