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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 222864Generated: October 25, 2026

4-Bromoaniline → (4-Bromo-phenyl)-(2-methyl-6-nitro-phenyl)-amine

https://huagongshe.com/reaction/222864

Reaction equation

Participants

RoleNameHCIDCharge
Reactant4-BromoanilineHCID 7807—
Reactant2-Fluoro-1-methyl-3-nitrobenzeneHCID 13470957—
ReactantPotassium tert-butoxideHCID 23665647—
SolventDimethyl SulfoxideHCID 679—
Product(4-Bromo-phenyl)-(2-methyl-6-nitro-phenyl)-amineHCID 68836228—

Reaction Steps

The product (2.44 g) is obtained according to the method of stage 1 of Example 4, by using 1.8 g of 2-fluoro-3-methyl-nitrobenzene and 3 g of 4-bromo-aniline in the presence of 2.09 g of potassium tert-butanolate in 20 mL of DMSO.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08207373B2
Source datasetuspto-grants-2012_06
ORD IDord-121fe60eaae74f4bb15f4c20ccd382f0
Source noteuspto-grants-2012_06