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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2232384Generated: November 1, 2026

1,2-Diiodoethane → HCID 14405318, compound

https://huagongshe.com/reaction/2232384

Reaction equation

Participants

RoleNameHCIDCharge
Reactant1,2-DiiodoethaneHCID 12224—
ReactantAmmonium ChlorideHCID 25517—
ReactantHCID 13215562HCID 13215562—
ReactantButyllithiumHCID 178418339—
SolventDiethyl EtherHCID 3283—
ProductHCID 14405318HCID 1440531867.4%

Reaction Steps

A solution of 2.3 grams (0.012 mole of 2-(4-chlorophenyl)thiazole in 20 ml of diethyl ether was cooled to -78° C. To this solution was added 4.72 ml of a 2.5M solution of n-butyllithium in hexanes. This mixture was stirred for 30 minutes. A solution of 3.3 grams (0.012 mole) of 1,2-diiodoethane in 15 ml of diethyl ether was added, and the resultant mixture was allowed to warm to room temperature and stir for approximately 18 hours. approximately 50 ml of an aqueous, saturated ammonium chloride solution was added, and the resultant mixture was poured into a separatory funnel. The organic phase was washed with water followed by an aqueous, saturated sodium chloride solution. The washed organic phase was dried over anhydrous sodium sulfate and was filtered. The filtrate was evaporated under reduced pressure leaving a residue. This residue was purified by column chromatography on silica gel, eluting with methylene chloride:n-hexane (3:1), to yield 2.6 grams of 2-(4-chlorophenyl)-5-iodothiazole as a solid.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04788207
Source datasetuspto-grants-1988_11
ORD IDord-e5f7b24864864d6d87c9336b3784180f
Source noteuspto-grants-1988_11