HRID2242436

反应详情

EQUATION

反应方程式

REACTANTS

反应物

结构：CC(C)(C)OC(=O)N[C@H](C(=O)NC1CCCC1)C(C)(C)C

HCID57892997

未命名化合物

结构：C=C[C@@H]1C[C@]1(NC(=O)[C@@H]1C[C@@H](Oc2cc(-c3ccccc3)nc3cc(OC)ccc23)C[C@H]1C(=O)OC(C)(C)C)C(=O)OCC

HCID59204175

未命名化合物

结构：C=C[C@@H]1C[C@]1(NC(=O)[C@@H]1C[C@@H](Oc2cc(-c3ccccc3)nc3cc(OC)ccc23)C[C@H]1C(=O)N[C@H](C(=O)N[C@H](C(=O)NC)C1CCCCC1)C(C)(C)C)C(=O)OCC

HCID59204178

未命名化合物

PRODUCTS

生成物

结构：C=C[C@@H]1C[C@]1(NC(=O)[C@@H]1C[C@@H](Oc2cc(-c3ccccc3)nc3cc(OC)ccc23)C[C@H]1C(=O)N[C@H](C(=O)NC1CCCC1)C(C)(C)C)C(=O)OCC

HCID11422715

未命名化合物

收率 63.2%

PROCEDURE

实验过程

Compound 51 (298 mg, 0.048 mmol) and 35 (16 mg, 0.054 mmol) was deprotected and coupled according to the method for the preparation of 39. Purification by HPLC (MeOH/H2O 90:10 with 0.2% triethylamine) gave 52 (22 mg, 63%) as a colorless solid.

WORKUP

后处理

customPurification by HPLC (MeOH/H2O 90:10 with 0.2% triethylamine)

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-ed651543a6ab4f89a5b3d7dd52afe77f
来源数据集: uspto-grants-2010_03
DOI: 10.6084/m9.figshare.5104873.v1
专利: US07671032B2
来源说明: uspto-grants-2010_03

反应 SMILES

C(O[C:6](=[O:21])[NH:7][C@H:8]([C:13](=[O:20])[NH:14][CH:15]1[CH2:19][CH2:18][CH2:17][CH2:16]1)[C:9]([CH3:12])([CH3:11])[CH3:10])(C)(C)C.C(OC([C@@H:29]1[CH2:33][C@H:32]([O:34][C:35]2[C:44]3[C:39](=[CH:40][C:41]([O:45][CH3:46])=[CH:42][CH:43]=3)[N:38]=[C:37]([C:47]3[CH:52]=[CH:51][CH:50]=[CH:49][CH:48]=3)[CH:36]=2)[CH2:31][C@H:30]1[C:53](=[O:65])[NH:54][C@:55]1([C:60]([O:62][CH2:63][CH3:64])=[O:61])[CH2:57][C@H:56]1[CH:58]=[CH2:59])=O)(C)(C)C.C(OC([C@@]1(NC([C@@H]2C[C@@H](OC3C4C(=CC(OC)=CC=4)N=C(C4C=CC=CC=4)C=3)C[C@H]2C(=O)N[C@H](C(=O)N[C@@H](C2CCCCC2)C(=O)NC)C(C)(C)C)=O)C[C@H]1C=C)=O)C>>[CH2:63]([O:62][C:60]([C@@:55]1([NH:54][C:53]([C@@H:30]2[CH2:31][C@@H:32]([O:34][C:35]3[C:44]4[C:39](=[CH:40][C:41]([O:45][CH3:46])=[CH:42][CH:43]=4)[N:38]=[C:37]([C:47]4[CH:48]=[CH:49][CH:50]=[CH:51][CH:52]=4)[CH:36]=3)[CH2:33][C@H:29]2[C:6](=[O:21])[NH:7][C@H:8]([C:13](=[O:20])[NH:14][CH:15]2[CH2:16][CH2:17][CH2:18][CH2:19]2)[C:9]([CH3:10])([CH3:11])[CH3:12])=[O:65])[CH2:57][C@H:56]1[CH:58]=[CH2:59])=[O:61])[CH3:64]