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HuagongsheHuagongshe Chemie-Druckbericht · Nur für Forschungszwecke
HRID 2242532Erstellt: 25. Oktober 2026

Sodium Chloride → Trandolapril

https://huagongshe.com/reaction/2242532

Reaktionsgleichung

Beteiligte Stoffe

RolleNameHCIDEinwaage
EduktSodium ChlorideHCID 5234—
EduktMethanaminium, N-((1H-benzotriazol-1-yloxy)(dimethylamino)methylene)-N-methyl-, hexafluorophosphate(1-) (1:1)HCID 2733084—
Edukt(2S,3aR,7aS)-octahydro-1H-indole-2-carboxylic acidHCID 7018901—
EduktN-(1-ethoxycarbonyl-3-phenylpropyl)-L-alanineHCID 13044262—
LösungsmittelDimethylformamideHCID 6228—
LösungsmittelAcetonitrileHCID 6342—
LösungsmittelTriethylamineHCID 8471—
ProduktTrandolaprilHCID 548472792%

Reaktionsschritte

To 2.79 g of (S)-1-(N-(1-(ethoxycarbonyl)-3-phenylpropyl)-L-alanine and 1.75 g of (2S,3aR,7aS)-octahydro-1H-indol-2-carboxylic acid in 100 ml of acetonitrile and 5 ml DMF first 2.9 ml of triethylamine and then with stirring 3.8 g O-(benzotriazol-1-yl)-N,N,N′,N′-tetramethyluronium hexafluorophosphate were and the stirring of the mixture was continued for 30 minutes at room temperature. Finally, 300 ml of saturated NaCl solution was added and the mixture was extracted twice with 100 ml of ethyl acetate. After isolation of the product, which was done by the same way as in example 1, 3.96 g (92%) of trandolapril was obtained.

Herkunft & Nachweise

DOI10.6084/m9.figshare.5104873.v1
PatentnummerUS07671215B2
Quelldatensatzuspto-grants-2010_03
ORD IDord-ea87d675a8b64bf4ac30b3d92c8d90c9
Quellennotizuspto-grants-2010_03