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HRID224807

反应详情

EQUATION

反应方程式

HRID 224807 的结构方程式

REACTANTS

反应物

2
结构：CC(=O)N1CCNC1=O
HCID79350

N-Acetyl-2-imidazolidinone

C5H8N2O2

结构：Cc1cc(N)n(C(C)C)n1
HCID121018

3-Methyl-1-(propan-2-yl)-1H-pyrazol-5-amine

C7H13N3

PRODUCTS

生成物

1
结构：CC(=O)N1CCN=C1Nc1cc(C)nn1C(C)C
HCID12763789

未命名化合物

PROCEDURE

实验过程

5-amino-1-isopropyl-3-methylpyrazole (J. Gen. Chem. USSR 31 234, 1961) (19.3 g.) and 1-acetyl-2-imidazolidinone (20.1 g.) were reacted as described in Example I to give 12.73 g. of product, mp 145°-147° C.

WORKUP

后处理

  1. customto give 12.73 g