HRID2250320

反应详情

EQUATION

反应方程式

HRID 2250320 的结构方程式

PROCEDURE

实验过程

Following the same procedure described for the preparation of compound 3a, the compound 3b was synthesized in 40% yield from compound 2 as a yellow oil. 1H NMR (300 MHz, CD3OD) δ 1.21 (m, 4H), 1.42 (m, 1H), 1.49 (m, 2H), 1.83 (d, 2H), 1.93 (m, 2H), 2.31 (m, 2H), 2.69 (m, 2H), 2.99 (m, 2H), 3.35 (m, 2H), 3.60 (m, 5H), 4.50 (m, 2H), 7.28 (m, 5H). m/z (ESI): 334 [C20H31NO3+H]+.