HRID2257745

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID7748

Ethyl bromoacetate

C4H7BrO2

结构：COc1cc2c(N3CCC(n4c(=O)c5cc(C)ccc5n(C)c4=O)CC3)ncnc2cc1O

HCID135847591

未命名化合物

PRODUCTS

生成物

结构：CCOC(=O)COc1cc2ncnc(N3CCC(n4c(=O)c5cc(C)ccc5n(C)c4=O)CC3)c2cc1OC

HCID22923438

未命名化合物

收率 89%

PROCEDURE

实验过程

The procedure similar to that described in Example 1 was repeated, except that 500.0 mg (1.12 mmol) of Compound 89 obtained in Example 79 was used in place of Compound 24 and ethyl bromoacetate was used in place of methyl iodide. As a result, 530.0 mg (yield: 89%) of Compound 93 was obtained as white crystals.

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-0fe2d92c480c40cfb306463d950373d5
来源数据集: uspto-grants-1997_08
DOI: 10.6084/m9.figshare.5104873.v1
专利: US05658917
来源说明: uspto-grants-1997_08

反应 SMILES

[OH:1][C:2]1[CH:11]=[C:10]2[C:5]([C:6]([N:12]3[CH2:17][CH2:16][CH:15]([N:18]4[C:27](=[O:28])[C:26]5[C:21](=[CH:22][CH:23]=[C:24]([CH3:29])[CH:25]=5)[N:20]([CH3:30])[C:19]4=[O:31])[CH2:14][CH2:13]3)=[N:7][CH:8]=[N:9]2)=[CH:4][C:3]=1[O:32][CH3:33].Br[CH2:35][C:36]([O:38][CH2:39][CH3:40])=[O:37]>>[CH2:39]([O:38][C:36]([CH2:35][O:1][C:2]1[CH:11]=[C:10]2[C:5]([C:6]([N:12]3[CH2:17][CH2:16][CH:15]([N:18]4[C:27](=[O:28])[C:26]5[C:21](=[CH:22][CH:23]=[C:24]([CH3:29])[CH:25]=5)[N:20]([CH3:30])[C:19]4=[O:31])[CH2:14][CH2:13]3)=[N:7][CH:8]=[N:9]2)=[CH:4][C:3]=1[O:32][CH3:33])=[O:37])[CH3:40]