p-Fluoronitrobenzene → HCID 25130784, compound

HRID 2262534Notes

Reaction equation

[NH:1]1[CH:5]=[C:4]([C:6]2[C:7]([C:15]3[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=3)=[N:8][O:9][C:10]=2[C:11]([F:14])([F:13])[F:12])[N:3]=[CH:2]1.F[C:22]1[CH:27]=[CH:26][C:25]([N+:28]([O-:30])=[O:29])=[CH:24][CH:23]=1>>[N+:28]([C:25]1[CH:26]=[CH:27][C:22]([N:1]2[CH:5]=[C:4]([C:6]3[C:7]([C:15]4[CH:16]=[CH:17][CH:18]=[CH:19][CH:20]=4)=[N:8][O:9][C:10]=3[C:11]([F:14])([F:12])[F:13])[N:3]=[CH:2]2)=[CH:23][CH:24]=1)([O-:30])=[O:29]

Participants

Reactant 2

HCID 9590p-Fluoronitrobenzene

HCID 178506308HCID 178506308, compound

Product 1

HCID 25130784HCID 25130784, compoundYield 12%

Procedure

As described for Example 3, 4-(1H-imidazol-4-yl)-3-phenyl-5-trifluoromethyl-isoxazole (70 mg, 0.25 mmol) was converted, using 4-fluoronitrobenzene instead of 4-fluoroacetophenone, to the title compound (12 mg, 12%) which was obtained as a yellow solid. MS: m/e=401.0 [M+H]+.

Sources & evidence

ORD record: ord-8c001e0910824fa295365eb32c4de2a4
Source dataset: uspto-grants-2010_12
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US07851469B2

Reaction notes

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