Hydrochloric Acid → 2-Chloro-6-(hydroxymethyl)-3-pyridinol

참여 물질

반응 조건

반응 단계

2-Chloro-3-pyridinol (20.0 g, 0.154 mole), NaHCO3 (19.5 g, 0.232 mole, 1.5 equ), and 150 mL of water are placed in a flask. The flask is placed in an oil bath at 90° C., and after 5 min, 37% aqueous formaldehyde (40.5 mL, 0.541 mole, 3.5 equ) is added in six unequal doses in the following order: 12 mL, 3×8 mL, then 2.2 mL all at 90-min intervals and then the final 2.3 mL after the reaction stirs for 15 h at 90° C. The reaction is stirred at 90° C. for another 4 h and then cooled by placing the flask in an ice bath. The pH of the reaction is then adjusted to 1 using 6N HCl. The reaction is stirred for 1.5 h in an ice bath allowing an undesired solid to form. The undesired solid is removed by filtration, and the filtrate is extracted seven times with EtOAc. The combined organic extracts are concentrated in vacuo, toluene is added to the flask and removed in vacuo to azeotrope water, and then CH2Cl2 is added and removed in vacuo to obtain 2-chloro-6-(hydroxymethyl)-3-pyridinol as a pale yellow solid (81% yield) sufficiently pure for subsequent reaction. MS (EI) for C6H6ClNO2, m/z: 159(M)+.

출처 및 근거