3,4-Difluorobenzylamine → HCID 18334142, compound

HRID 2269512Notes

Reaction equation

HRID 2269512 reaction equation
[N+:1]([C:4]1[CH:5]=[C:6]([C:10]([C:12]2[CH:17]=[CH:16][C:15]([O:18][CH3:19])=[CH:14][CH:13]=2)=O)[CH:7]=[CH:8][CH:9]=1)([O-:3])=[O:2].[F:20][C:21]1[CH:22]=[C:23]([CH:26]=[CH:27][C:28]=1[F:29])[CH2:24][NH2:25]>>[F:20][C:21]1[CH:22]=[C:23]([CH:26]=[CH:27][C:28]=1[F:29])[CH2:24][NH:25][CH:10]([C:12]1[CH:17]=[CH:16][C:15]([O:18][CH3:19])=[CH:14][CH:13]=1)[C:6]1[CH:7]=[CH:8][CH:9]=[C:4]([N+:1]([O-:3])=[O:2])[CH:5]=1

Participants

3

Reactant 2

HCID 1235723,4-DifluorobenzylamineHCID 794540(4-Methoxyphenyl)(3-nitrophenyl)methanone

Product 1

HCID 18334142HCID 18334142, compoundYield 95.5%

Procedure

Following a similar procedure to that described in Example (1a), 8.91 g of 4-methoxyphenyl 3-nitrophenyl ketone and 4.96 g of 3,4-difluorobenzylamine were reacted, to obtain 12.72 g of the title compound as a pale yellow oil.

Workup

  1. customwere reacted

Sources & evidence

ORD record
ord-01545079881c415ea879b6fbe5e6f12c
Source dataset
uspto-grants-2001_12
Patent number
US06329405B1

Reaction notes

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