huagongshe.com
HRID228014

反应详情

EQUATION

反应方程式

HRID 228014 的结构方程式

REACTANTS

反应物

2
结构：CCC(C)c1ccc(N)cc1
HCID121771

Benzenamine, 4-(1-methylpropyl)-

C10H15N

结构：N#C[C@@H]1C[C@H](F)CN1C(=O)CNC12CCC(C(=O)O)(CC1)CC2
HCID57634365

未命名化合物

PRODUCTS

生成物

1
结构：CCC(C)c1ccc(NC(=O)C23CCC(NCC(=O)N4C[C@@H](F)C[C@H]4C#N)(CC2)CC3)cc1
HCID57756815

未命名化合物

收率 18.5%

PROCEDURE

实验过程

In a similar manner to Example 63, (2S,4S)-1-[[N-(4-carboxybicyclo[2.2.2]oct-1-yl)amino]acetyl]-4-fluoropyrrolidine-2-carbonitrile (50.0 mg) and 4-sec-butylaniline (51.5 mg) were used to obtain (2S,4S)-4-fluoro-1-[[N-[4-[N-[4-(1-methylpropyl)phenyl]amino]carbonylbicyclo[2.2.2]oct-1-yl]amino]acetyl)pyrrolidine-2-carbonitrile (13.0 mg).