HRID2283715

反应详情

EQUATION

反应方程式

HRID 2283715 的结构方程式

PROCEDURE

实验过程

In accordance with Example 70 (Step 1), 6-bromo-4-methoxy-1H-indazole (329 mg) was used instead of 5-bromo-7-methyl-1H-indazole to obtain 6-bromo-1-ethyl-4-methoxy-1H-indazole (210 mg) and 6-bromo-2-ethyl-4-methoxy-2H-indazole.