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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2285140Generated: October 31, 2026

Sodium Iodide → HCID 86687153, compound

https://huagongshe.com/reaction/2285140

Reaction equation

Participants

RoleNameHCIDCharge
ReactantSodium IodideHCID 5238—
Reactant(1R,4S)-4-Amino-1,2,3,4-tetrahydronaphthalen-1-olHCID 86686674—
ReactantHCID 86687152HCID 86687152—
SolventWaterHCID 962—
SolventDimethylformamideHCID 6228—
ProductHCID 86687153HCID 8668715368%

Reaction Steps

To a solution of Intermediate A (102 mg, 0.63 mmol) in DMF (1.5 mL) was added NaI (60% dispersion in oil, 68 mg, 1.71 mmol). The mixture was stirred at RT for 5 min, then a solution of Intermediate 94b (240 mg, 0.57 mmol) in DMF (1.5 mL) was added and the mixture stirred at 60° C. for 1.25 h. The cooled mixture was diluted with water and extracted with DCM (4×25 mL). The combined organics were dried and concentrated in vacuo. The residue was purified by FCC, using 0-10% (2M NH3 in MeOH) in DCM, to give the title compound as a pale brown gum (219 mg, 68%). LCMS (Method 3): Rt 2.65 min, m/z 565 [MH+].

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS09145413B2
Source datasetuspto-grants-2015_09
ORD IDord-b84143c0fe9a46e08bd16104c28f779f
Source noteuspto-grants-2015_09