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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2287298Generated: November 1, 2026

Iodoethane → 10-ethylphenoxazine

https://huagongshe.com/reaction/2287298

Reaction equation

Participants

RoleNameHCIDCharge
ReactantIodoethaneHCID 6340—
ReactantPotassium CarbonateHCID 11430—
ReactantPotassium HydroxideHCID 14797—
ReactantPhenoxazineHCID 67278—
CatalystTetrabutylammonium hydrogen sulfateHCID 94433—
SolventTolueneHCID 1140—
Product10-ethylphenoxazineHCID 328622778.5%

Reaction Steps

Into a reaction flask were introduced 3.0 g (16.4 mmol) of phenoxazine, 6.5 g (98.5 mmol) of 85% KOH, 3.7 g (26.8 mmol) of potassium carbonate, 577 mg (1.7 mmol) of tetra-n-butylammonium hydrogensulfate, and 100 ml of toluene. Thereto was gradually added 5.1 g (32.7 mmol) of ethyl iodide with a dropping funnel (slight heat generation occurred). Subsequently, the mixture was reacted at 60 to 80° C. for 7 hours. After the disappearance of the phenoxazine was ascertained by TLC and gas chromatography, the resultant toluene solution was cooled, washed with water three times, dried (with MgSO4), and then concentrated. The residue was distilled under vacuum to obtain 2.72 g of 10-ethylphenoxazine. Yield, 78.7%; b.p., 120-122° C./1 mmHg.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06083651
Source datasetuspto-grants-2000_07
ORD IDord-33984304e15049f9a7fb694aa957f065
Source noteuspto-grants-2000_07