HRID2288268

反应详情

EQUATION

反应方程式

REACTANTS

反应物

反应SMILES：Cc1cn([C@H]2C[C@H](O)[C@@H](CO[Si](c3ccccc3)(c3ccccc3)C(C)(C)C)O2)c(=O)[nH]c1=O

HCID11812846

未命名化合物

反应SMILES：Cc1cn([C@@]2(COCc3ccccc3)C[C@H](O)[C@@H](CO[Si](c3ccccc3)(c3ccccc3)C(C)(C)C)O2)c(=O)[nH]c1=O

HCID131719888

未命名化合物

反应SMILES：Cc1cn([C@@]2(COCc3ccccc3)C[C@H](OC(=S)Oc3ccccc3)[C@@H](CO[Si](c3ccccc3)(c3ccccc3)C(C)(C)C)O2)c(=O)[nH]c1=O

HCID131720249

未命名化合物

2 次

PRODUCTS

产物

反应SMILES：C=CC[C@H]1C[C@H](n2cc(C)c(=O)[nH]c2=O)O[C@@H]1CO[Si](c1ccccc1)(c1ccccc1)C(C)(C)C

HCID15450808

未命名化合物

收率 58%

PROCEDURE

实验过程

Utilizing the procedures of Examples 16 and 17 wherein compound 18 was obtained from compound 3 via compound 17, compound 2 is used as the starting material in place of compound 3. Compound 2 is converted via the procedure of Example 16 to an intermediate compound similar to compound 17 except this intermediate differs from compound 17 in that it does not have a blocking group on its heterocyclic base. The intermediate is then treated as per the procedure of Example 17 to give the title compound in 58% yield.

WORKUP

后处理

additionThe intermediate is then treated as per the procedure of Example 17

来源与证据

来源类型: Open Reaction Database
ORD记录: ord-9483a2f9c0b14cb6b75aecd0ef6e452d
来源数据集: uspto-grants-2000_07
DOI: 10.6084/m9.figshare.5104873.v1
专利号: US06087482
来源说明: uspto-grants-2000_07

反应SMILES

C(OC[C@@:10]1([N:35]2[CH:43]=[C:41]([CH3:42])[C:39](=[O:40])[NH:38][C:36]2=[O:37])[O:34][C@H:14]([CH2:15][O:16][Si:17]([C:30]([CH3:33])([CH3:32])[CH3:31])([C:24]2[CH:29]=[CH:28][CH:27]=[CH:26][CH:25]=2)[C:18]2[CH:23]=[CH:22][CH:21]=[CH:20][CH:19]=2)[C@@H:12](O)[CH2:11]1)C1C=CC=CC=1.[Si](OC[C@H]1O[C@@H](N2C=C(C)C(=O)NC2=O)C[C@@H]1O)(C(C)(C)C)(C1C=CC=CC=1)[C:45]1[CH:50]=CC=C[CH:46]=1.C(OC[C@@]1(N2C=C(C)C(=O)NC2=O)O[C@H](CO[Si](C(C)(C)C)(C2C=CC=CC=2)C2C=CC=CC=2)[C@@H](OC(OC2C=CC=CC=2)=S)C1)C1C=CC=CC=1>>[CH2:50]([C@@H:12]1[C@@H:14]([CH2:15][O:16][Si:17]([C:30]([CH3:31])([CH3:32])[CH3:33])([C:18]2[CH:19]=[CH:20][CH:21]=[CH:22][CH:23]=2)[C:24]2[CH:29]=[CH:28][CH:27]=[CH:26][CH:25]=2)[O:34][C@@H:10]([N:35]2[CH:43]=[C:41]([CH3:42])[C:39](=[O:40])[NH:38][C:36]2=[O:37])[CH2:11]1)[CH:45]=[CH2:46]