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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2292110Generated: November 3, 2026

Water → m-Chlorophenethylic alcohol

https://huagongshe.com/reaction/2292110

Reaction equation

Participants

RoleNameHCIDCharge
ReactantWaterHCID 962—
Reactant3-Chlorophenylacetic acidHCID 15879—
ReactantAluminium lithium hydrideHCID 21226445—
SolventDiethyl EtherHCID 3283—
Productm-Chlorophenethylic alcoholHCID 7885699.7%

Reaction Steps

Lithium aluminium hydride (19 g,) was suspended in dry ether (300 ml) and 3-chlorophenylacetic acid (58 g,) in dry ether (600 ml) was added dropwise to the stirred suspension over 1 hr. The mixture was then heated at reflux for 2 hr. when tlc indicated completion of reaction. Excess lithum aluminium hydride was carefully decomposed with water (500 ml). The ether layer was separated off and 2M hydrochloric acid was used to break up the gelatinous aqueous layer which was then extracted with ether (2×400 ml). The combined ether layers were washed with water (300 ml), dried (sodium sulphate) and evaporated in vacuo to give 2-(3-chlorophenyl)ethanol as a pale yellow oil (53.1 g) characterised by its nmr spectrum.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04801593
Source datasetuspto-grants-1989_01
ORD IDord-76c831d3af1b44569612e66177534a5b
Source noteuspto-grants-1989_01