Nitric Acid → 2-Ethyl-4-fluoro-1-nitrobenzene
Reaction equation
[CH2:1]([C:3]1[CH:4]=[C:5]([F:9])[CH:6]=[CH:7][CH:8]=1)[CH3:2].[N+:10]([O-])([OH:12])=[O:11]>>[N+:10]([C:8]1[CH:7]=[CH:6][C:5]([F:9])=[CH:4][C:3]=1[CH2:1][CH3:2])([O-:12])=[O:11]Participants
3
Procedure
3-ethyl-fluorobenzene was reacted with nitric acid to obtain 4-nitro-3-ethyl-fluorobenzene which was reacted with N-hydroxy-phthalimide to form 0-(4-nitro-3-ethyl-phenoxy)-phthalimide which was reacted to form 0-(4-nitro-3-ethylphenyl)-hydroxylamine melting at 55°-56° C.
Sources & evidence
- ORD record
- ord-b0425c33d1304d5cbf8fabf6a994ca30
- Source dataset
- uspto-grants-1989_01
- Patent number
- US04801717
Reaction notes
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