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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2293947Generated: October 31, 2026

Phenothiazine → 10-(3-chloropropyl)-10H-phenothiazine

https://huagongshe.com/reaction/2293947

Reaction equation

Participants

RoleNameHCIDCharge
ReactantPhenothiazineHCID 7108—
Reactant1-Bromo-3-chloropropaneHCID 8006—
ReactantSodium hydrideHCID 24758—
ReactantAmmonium ChlorideHCID 25517—
SolventDimethylformamideHCID 6228—
Product10-(3-chloropropyl)-10H-phenothiazineHCID 1229912080%

Reaction Steps

To a solution of phenothiazine (4.0 g, 0.02 mol) in dry dimethylformamide (100 ml) kept under an atmosphere of nitrogen, sodium hydride (1.0 g, 0.025 mol, 60% dispersion in oil) was carefully added. The reaction mixture was left stirring for 15 minutes. 1-Bromo-3-chloropropane (8.0 g, 0.05 mol) was added and the mixture was left stirring overnight. Ammonium chloride (2.0 g, 0.04 mol) was added, and after continued stirring for 30 minutes the solution was poured onto water (300 ml). The mixture was extracted with dichloromethane (2×200 ml). The combined organic extracts were dried (MgSO4), filtered and the solvent evaporated. This afforded a residue which was purified by column chromatography on silica gel (250 g) using a mixture of n-heptane and ethyl acetate (9:1) as eluent. 4.4 g (80%) of 10-(3-chloropropyl)-10H-phenothiazine was obtained as an oil. Rf : 0.55 (SiO2 ; n-heptane/ethyl acetate=1:1).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05688788
Source datasetuspto-grants-1997_11
ORD IDord-73210953228545c5a357f770972f88bb
Source noteuspto-grants-1997_11