Aluminum(III) Chloride → HCID 20442868, compound

Participants

Reaction Steps

The procedure of Example 6 was repeated by using 250 mg of 2,6-dibutoxy-4-methoxy-4-methyl-2,5-cyclohexadienone and 20 mg of aluminum chloride, recovering 234 g of an oily crude product. The crude product was purified by silica gel column chromatography using a 20:1 benzene-ethyl acetate mixture, giving 217 mg of 2,6-dibutoxy-4-methylidene-2,5-cyclohexadienone in 87% of theoretical yield. The compound thus obtained was identified by NMR.

Provenance & Evidence