HRID2300626

反应详情

EQUATION

反应方程式

HRID 2300626 的结构方程式

PROCEDURE

实验过程

The title compound was prepared (as described above for the preparation of Example 2) from 75 mg (0.195 mmol) of Intermediate 46 and 34 mg (0.2 mmol) of Intermediate 16 to yield 32 mg of Example 8: TLC (DCM/MeOH, 4/1): Rf=0.63; 1H NMR (DMSO-d6, 300 MHz) δ11.57 (d, 1H, J=9.6), 7.97 (m, 2H), 7.86 (d, 1H, J=7.2), 7.42 (m, 5H), 7.18 (d, 2H, 8.4), 6.87 (d, 2H, J=8.4), 5.61 (s, 1H), 4.20 (t, 2H, J=6.6), 4.14 (m, 1H), 3.22 (m, 2H), 2.94 (t, 2H, J=6.6), 2.83 (dd, 1H, J=13.8, 9.3); low resolution MS (ES+)m/e 543 (MH+).