HRID2300631

反应详情

EQUATION

反应方程式

HRID 2300631 的结构方程式

PROCEDURE

实验过程

The title compound was prepared (as described above for the preparation of Example 12) from 677 mg (1.85 mmol) of Intermediate 45 and 366 mg (1.85 mmol) of Intermediate 38 to yield 482 mg (46% yield) of Example 16. TLC (DCM/MeOH (4:1): Rf=0.55; 1H NMR (DMSO-d6, 300 MHz) δ11.39 (d, 1H, J=8.9), 7.86 (m, 2H), 7.69-7.59 (m, 1H), 7.54-7.40 (m, 4H), 7.10 (d, 2H, J=8.5), 6.79 (d, 2H, J=8.5), 5.3 (s, 1H), 4.12 (t, 2H, J=6.5), 4.1 (m, 1H), 3.16 (m, 1H), 2.86 (t, 2H, J=6.5), 2.76 (dd, 1H, J=13.7, 8.9), 2.3 (s, 3H), 1.64 (s, 3H): low resolution MS (ES+)m/e 565.1 (MH+).