HRID2300632

反应详情

EQUATION

反应方程式

HRID 2300632 的结构方程式

PROCEDURE

实验过程

The title compound was prepared (as described above for the preparation of Example 2) from 75 mg (0.177 mmol) of Intermediate 51 and 34 mg (0.194 mmol) of Intermediate 16 to yield 30 mg of Example 17: TLC (DCM/MeOH (4:1): Rf=0.63; 1H NMR (DMSO-d6, 400 MHz) δ11.49 (d, 1H, J=9.6), 7.77 (m, 4H), 7.37 (m, 3H), 7.10 (d, 2H, J=8.8), 6.97 (d, 2H, J=9.2), 6.79 (d, 2H, J=9.2), 5.54 (s, 1H), 4.66 (septuplet, 1H, J=6.0), 4.12 (t, 2H, J=6.8), 4.04 (m, 1H), 3.35 (m, 1H), 3.11 (m, 1H), 2.84 (t, 2H, J=6.8), 2.72 (dd, 1H, J=13.9, 9.2), 2.28 (s, 3H), 1.99 (m, 2H), 1.26 (d, 6H, J=6.0), 0.91 (m 3H, J=7.6); low resolution MS (ES+)m/e 583.1 (MH+).