HRID2300632
反应详情
EQUATION
反应方程式
REACTANTS
反应物
PRODUCTS
生成物
PROCEDURE
实验过程
The title compound was prepared (as described above for the preparation of Example 2) from 75 mg (0.177 mmol) of Intermediate 51 and 34 mg (0.194 mmol) of Intermediate 16 to yield 30 mg of Example 17: TLC (DCM/MeOH (4:1): Rf=0.63; 1H NMR (DMSO-d6, 400 MHz) δ11.49 (d, 1H, J=9.6), 7.77 (m, 4H), 7.37 (m, 3H), 7.10 (d, 2H, J=8.8), 6.97 (d, 2H, J=9.2), 6.79 (d, 2H, J=9.2), 5.54 (s, 1H), 4.66 (septuplet, 1H, J=6.0), 4.12 (t, 2H, J=6.8), 4.04 (m, 1H), 3.35 (m, 1H), 3.11 (m, 1H), 2.84 (t, 2H, J=6.8), 2.72 (dd, 1H, J=13.9, 9.2), 2.28 (s, 3H), 1.99 (m, 2H), 1.26 (d, 6H, J=6.0), 0.91 (m 3H, J=7.6); low resolution MS (ES+)m/e 583.1 (MH+).