HRID2300636
反应详情
EQUATION
反应方程式
REACTANTS
反应物
PRODUCTS
生成物
PROCEDURE
实验过程
The title compound was prepared (as described above for the preparation of Example 2) from 100 mg (0.27 mmol) of Intermediate 45 and 54 mg (0.27 mmol) of Intermediate 28 to yield 76 mg of Example 24: TLC (DCM/MeOH (4:1): Rf=0.52; 1H NMR (DMSO-d6, 300 MHz) δ11.52 (d, 1H, J=9.6), 7.97 (m, 2H), 7.87 (d, 2H, J=8.6), 7.55 (m, 5H), 7.18 (d, 2H, J=8.5), 6.86 (d, 2H, J=8.5), 5.59 (s, 1H), 4.21 (t, 2H, J=6.1), 4.09 (m, 1H), 3.22 (m, 1H), 2.96 (t, 2H, J=6.1), 2.78 (dd, 1H, J=13.9, 9.4), 2.39 (s, 3H), 1.73 (s, 3H).