HRID2300636

反应详情

EQUATION

反应方程式

HRID 2300636 的结构方程式

PROCEDURE

实验过程

The title compound was prepared (as described above for the preparation of Example 2) from 100 mg (0.27 mmol) of Intermediate 45 and 54 mg (0.27 mmol) of Intermediate 28 to yield 76 mg of Example 24: TLC (DCM/MeOH (4:1): Rf=0.52; 1H NMR (DMSO-d6, 300 MHz) δ11.52 (d, 1H, J=9.6), 7.97 (m, 2H), 7.87 (d, 2H, J=8.6), 7.55 (m, 5H), 7.18 (d, 2H, J=8.5), 6.86 (d, 2H, J=8.5), 5.59 (s, 1H), 4.21 (t, 2H, J=6.1), 4.09 (m, 1H), 3.22 (m, 1H), 2.96 (t, 2H, J=6.1), 2.78 (dd, 1H, J=13.9, 9.4), 2.39 (s, 3H), 1.73 (s, 3H).