HRID2300643

反应详情

EQUATION

反应方程式

HRID 2300643 的结构方程式

PROCEDURE

实验过程

The title compound was prepared (as described above for the preparation of Example 2) from 100 mg (0.27 mmol) of Intermediate 45 and 49 mg (0.27 mmol) of Intermediate 32 to yield 83 mg of Example 35: TLC (EtOAc/MeOH (7:3): Rf=0.28; 1H NMR (DMSO-d6, 400 MHz) δ11.38 (d, 1H, J=7.00), 7.84 (m. 4H), 7.45 (m, 3H), 7.16 (t, 2H, J=8.72), 7.09 (d, 2H, J=7.69), 6.77 (d, 2H, J=7.69), 5.49 (s, 1H), 4.11 (m, 2H), 4.01(m, br, 1H), 3.13 (m, 1H), 2.86 (m, 2H), 2.72 (s, br, 1H), 2.30 (s, 3H), 1.62 (s, 3H); low resolution MS (ES+) m/e 529 (MH+); RP-HPLC (Vydac C-18, 25 cm×4.6 mm; 30-100% CH3CN in H2O) with 0.1% HCO2H buffer: 30 minutes; 1 mL/min: tr=20.10 min (to=1.53).