HRID2300645

反应详情

EQUATION

反应方程式

HRID 2300645 的结构方程式

PROCEDURE

实验过程

The title compound was prepared (as described above for the preparation of Example 12) from 120 mg (0.33 mmol) of Intermediate 45 and 59 mg (0.33 mmol) of Intermediate 40 to yield 32 mg (18% yield) of Example 38: TLC (DCM/MeOH (4:1): Rf=0.72; 1H NMR (DMSO-d6, 300 MHz) δ11.43 (d, 1H, J=9.8), 7.97 (m, 2H), 7.56 (m, 5 h), 7.28 (m, 1H), 7.19 (d, 2H, J=8.0) 6.91 (d, 2H, J=8.0), 5.34 (s, 1H), 4.21 (m, 3H), 3.21 (m, 2H), 2.98 (t, 2H, J=6.6), 2.84 9 m, 1H), 2.40 (s, 3H), 1.78 (s, 3H); low resolution MS (ES+)m/e 547 (MH+).