HRID2300646

反应详情

EQUATION

反应方程式

HRID 2300646 的结构方程式

PROCEDURE

实验过程

The title compound was prepared (as described above for the preparation of Example 2) from 100 mg (0.27 mmol) of Intermediate 45 and 52 mg (0.27 mmol) of Intermediate 22 to yield 126 mg of Example 41. TLC (EtOAc/MeOH (7:3): Rf=0.44: 1H NMR (DMSO-d6, 400 MHz) δ11.30 (d, 1H, J=7.00), 7.87 (m. 2H), 7.73 (d, 2H, J=8.72), 7.45 (m, 3H), 7.10 (d, 2H, J=8.37), 6.88 (d, 2H, J=8.89), 6.77 (d, 2H, J=8.37), 5.74 (s, 1H), 4.11 (m, 2H), 4.01(m, br, 1H), 3.13 (m, 1H), 2.86 (m, 2H), 2.72 (m, 1H), 2.31 (s, 3H), 1.65 (s, 3H); low resolution MS (ES−) m/e 539 (M-H); RP-HPLC (Vydac C-18, 25 cm×4.6 mm; 10-50% CH3CN in H2O) with 0.1% HCO2H buffer: 30 minutes