HRID2300649

反应详情

EQUATION

反应方程式

HRID 2300649 的结构方程式

PROCEDURE

实验过程

The title compound was prepared as described above for the preparation of Example 2, from 102 mg (0.28 mmol) of Intermediate 45 and 69 mg (0.28 mmol) of Intermediate 19 to yield 77 mg of Example 45: TLC (EtOAc/MeOH , 713): Rf=0.56; 1H NMR (DMSO-d6, 400 MHz) δ11.55 (d, 1H, J=9.6), 7.86 (d, 2H, J=6.8), 7.76 (d, 2H, J=6.4), 7.46. (m, 3H), 7.38 (m, 3H), 7.10 (d, 2H, J=8.4), 6.78 (d, 2H, J=8.4), 5.5 (s, 1H), 4.10 (t, 2H, J=6.6), 4.0 (m, 1H), 3.16 (m, 1H), 2.86 (t, 2H, J=6.5), 2.69 (dd, 1H, J=13.6, 9.6), 2.31 (s, 3H), 1.87 (m, 2H), 1.25-1.1 (m, 10H), 0.78 (t, 3H, J=6.8); low resolution MS (ES+)m/e 595.1 (MH+).