Pyridine → 3-acetoxy-4-chloro-10H-phenothiazine
Reaction equation
[Cl:1][C:2]1[C:15]2[S:14][C:13]3[C:8](=[CH:9][CH:10]=[CH:11][CH:12]=3)[NH:7][C:6]=2[CH:5]=[CH:4][C:3]=1[OH:16].N1C=CC=CC=1.[C:23](OC(=O)C)(=[O:25])[CH3:24]>O>[C:23]([O:16][C:3]1[CH:4]=[CH:5][C:6]2[NH:7][C:8]3[C:13]([S:14][C:15]=2[C:2]=1[Cl:1])=[CH:12][CH:11]=[CH:10][CH:9]=3)(=[O:25])[CH3:24]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
To a solution of 1.8 g of 4-chloro-3-hydroxy-10H-phenothiazine (see Example 3) in 20 ml of acetic anhydride was added 1.2 ml of pyridine. The reaction mixture was then stirred at ambient temperature for 12 hours and then poured in water (75 ml). The resulting precipitate was filtered, washed with water and dried under vacuum to give 1.65 g of 3-acetoxy-4-chloro-10H-phenothiazine (m.p.: 173° C.).
Workup
- filtrationThe resulting precipitate was filtered
- washwashed with water
- customdried under vacuum
Sources & evidence
- ORD record
- ord-e422749e714e492081fd94dafe2a4152
- Source dataset
- uspto-grants-1989_07
- Patent number
- US04845083
Reaction notes
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