HRID231207
反应详情
EQUATION
反应方程式
REACTANTS
反应物
PRODUCTS
生成物
AUXILIARIES
试剂、催化剂与溶剂
PROCEDURE
实验过程
By reacting 0.85 mmole of phenyl benzoate in 6 ml of DME with 3.38 m atoms of samarium, in the conditions of example 9, a dark-brown compound (phenyl benzoate-samarium) has been obtained and treated as usually. Benzoate was quantitatively converted.