HRID2353238

反应详情

EQUATION

反应方程式

HRID 2353238 的结构方程式

PROCEDURE

实验过程

The title compound (98 mg, 97%) was prepared from the compound from step 1 (100 mg, 0.29 mmol) and 1N NaOH (0.29 mL, 0.29 mmol) by the procedure described in Example 2: MS (ESI) m/z 327 (M+H); 1H NMR (400 MHz, CD3OD) δ 2.44 (m, 2H), 2.72 (t, J=4.8 Hz, 4H), 2.78 (t, J=8.0 Hz, 2H), 3.17 (t, J=4.8 Hz, 4H), 6.88-6.92 (m, 4H), 6.97-7.04 (m, 3H), 7.28 (m, 2H).