HRID2353240

反应详情

EQUATION

反应方程式

HRID 2353240 的结构方程式

PROCEDURE

实验过程

The title compound (96 mg, 95%) was prepared from the compound from step 1 (100 mg, 0.30 mmol) and 1N NaOH (0.3 mL, 0.3 mmol) by the procedure described in Example 2: MS (ESI) m/z 313 (M+H); 1H NMR (400 MHz, DMSO-d6) δ 2.57 (t, J=4.8 Hz, 4H), 2.67 (s, 2H), 3.07 (t, J=4.8 Hz, 4H), 6.89-6.96 (m, 6H), 7.04 (m, 1H), 7.32 (m, 2H).