Sodium Iodide → 2-((2-Chloro-4-nitrophenoxy)methyl)pyridine

Participants

Reaction Conditions

Reaction Steps

2-chloro-4-nitro phenol (10 g, 57.6 mmol, 1 equiv), 2-pycolyl chloride hydrogen chloride (9.45 g, 57.6 mmol, 1 equiv) cesium carbonate 41.3 (126.8 mmol, 2.2 equiv) and sodium iodide (8.64 g, 57.6 mmol, 1 equiv) were suspended in 200 mL acetonitrile. The reaction mixture was stirred at 60° C. for 5 h. The resulted suspension was filtered and washed with water (400 mL), yielding 2-(2-chloro-4-nitro-phenoxymethyl)-pyridine (8 g, 52%) as a red solid.

Provenance & Evidence