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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2357414Generated: November 1, 2026

2-Fluoro-4-iodoaniline → 2,3-difluoro-N-(2-fluoro-4-iodophenyl)-5-(2-methoxyethoxy)-6-nitroaniline

https://huagongshe.com/reaction/2357414

Reaction equation

Participants

RoleNameHCIDCharge
Reactant2-Fluoro-4-iodoanilineHCID 185694—
Reactant1,2,3-Trifluoro-5-(2-methoxyethoxy)-4-nitrobenzeneHCID 59386372—
Product2,3-difluoro-N-(2-fluoro-4-iodophenyl)-5-(2-methoxyethoxy)-6-nitroanilineHCID 5938630132%

Reaction Steps

2-Fluoro-4-iodoaniline (1.6 g, 6.8 mmol) and 1,2,3-trifluoro-5-(2-methoxyethoxy)-4-nitrobenzene (1.7 g, 6.8 mmol) were reacted using the condition described in Example 1 (Step A) to form the title compound (1.02 g, 32%); m/z=467 [M−1].

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07759518B2
Source datasetuspto-grants-2010_07
ORD IDord-b3135a6009264b8ca90d7c1d09a7435c
Source noteuspto-grants-2010_07