2-Ethoxy-3-(4-nitrophenyl)prop-2-enoic acid → HCID 11424340, compound
Reaction equation
[CH2:1]([O:3][C:4](=[CH:8][C:9]1[CH:14]=[CH:13][C:12]([N+:15]([O-])=O)=[CH:11][CH:10]=1)[C:5]([OH:7])=[O:6])[CH3:2]>CO.[Pd]>[CH2:1]([O:3][CH:4]([CH2:8][C:9]1[CH:10]=[CH:11][C:12]([NH2:15])=[CH:13][CH:14]=1)[C:5]([OH:7])=[O:6])[CH3:2]Participants
4
Reactant 1
Product 1
Reagents, catalysts & solvents 2
Procedure
2-Ethoxy-3-(4-nitrophenyl)acrylic acid (18.4 g wet, approx. 77.5 mmol) was dissolved in MeOH (1.1 L) and 10% Pd on C (wet basis) (1.84 g) was added. The mixture was hydrogenated at 12 psi for 10 mins, followed by repeated refill to 20-28 psi every 10-m 20 mins for 5 hr then 46 psi for 18 hr. The mixture was filtered through GF/F paper and the residue was slurried in IMS (100 ml), filtered, washed with heptane (100 ml), and suction dried on the filter. Thus (±)-2-ethoxy 3-(4′-Aminophenyl)-propionic acid was obtained as an off-white solid (11.2 g, 69%).
Workup
- customfor 5 hr
- wait46 psi for 18 hr
- filtrationThe mixture was filtered through GF/F paper
- filtrationfiltered
- washwashed with heptane (100 ml), and suction
- customdried on the filter
Sources & evidence
- ORD record
- ord-d7daae631ef5409094772885027bc928
- Source dataset
- uspto-grants-2014_04
- Patent number
- US08710100B2
Reaction notes
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