Sulfuric Acid → 6-(4-Trifluoromethylphenylthio)-3-hexen-2-one
Reaction equation
O[CH:2]([CH2:7][CH2:8][S:9][C:10]1[CH:15]=[CH:14][C:13]([C:16]([F:19])([F:18])[F:17])=[CH:12][CH:11]=1)[CH2:3][C:4](=[O:6])[CH3:5].S(=O)(=O)(O)O>C1(C)C=CC=CC=1>[F:18][C:16]([F:17])([F:19])[C:13]1[CH:14]=[CH:15][C:10]([S:9][CH2:8][CH2:7][CH:2]=[CH:3][C:4](=[O:6])[CH3:5])=[CH:11][CH:12]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
1.46 Grams of 4-hydroxy-6-(4-trifluoromethylphenylthio)-2-hexanone were dissolved in 15 ml of toluene, and 0.35 g of concentrated aqueous sulfuric acid solution was added thereto. The resulting mixture was refluxed for 15 minutes with stirring, allowed to cool and then treated in the same manner as in Production example 34. Thus, 1.15 g of 6-(4-trifluoromethylphenylthio)-3-hexen-2-one (trans cis =4.2 : 1) were obtained (purity: 68.0%). The yield was 57.1%. Percent recovery of the starting material was 32.0%.
Workup
- temperatureThe resulting mixture was refluxed for 15 minutes
- temperatureto cool
- additiontreated in the same manner as in Production example 34
Sources & evidence
- ORD record
- ord-7c50a2ffcd70477bac47dfe2a519ed7d
- Source dataset
- uspto-grants-1992_03
- Patent number
- US05101076
Reaction notes
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