HRID237428

反应详情

EQUATION

反应方程式

HRID 237428 的结构方程式

PROCEDURE

实验过程

4-{4-[4-(2-Methanesulfonyl-ethoxy)-indazol-1-yl]-pyrimidin-2-ylamino}-cyclohexanecarboxylic acid ethyl ester was prepared by reaction of 4-amino-cyclohexanecarboxylic acid ethyl ester with 4-(2-methanesulfonyl-ethoxy)-1-[2-(propane-1-sulfonyl)-pyrimidin-4-yl]-1H-indazole following generally the procedure of Example 5.