HRID2375357

反应详情

EQUATION

反应方程式

HRID 2375357 的结构方程式

PROCEDURE

实验过程

The title compound was prepared in analogy to method 1.5 from 4-methyl-5-(1H-pyrrol-2-yl)-4H-1,2,4-triazole-3-thiol (1.43 mmol, 0.26 g) and 1-[2-(3-chloropropyl)-2,3-dihydro-1H-isoindol-5-yl]propan-1-one (1.43 mmol, 0.36 g; preparation in analogy to 1.4 from isoindoline as disclosed in WO 0125200). Yield: 0.11 g.