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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2384917Generated: November 2, 2026

Formaldehyde → 2-(4-chloro-phenyl)-6-[3-methoxy-4-(1-methyl-azetidin-3-yloxy)-phenyl]-6H-thieno[2,3-c]pyridin-7-one

https://huagongshe.com/reaction/2384917

Reaction equation

Participants

RoleNameHCIDCharge
ReactantFormaldehydeHCID 712—
ReactantMethanolHCID 887—
ReactantSodium cyanoborohydrideHCID 5003444—
Reactant6-[4-(Azetidin-3-yloxy)-3-methoxy-phenyl]-2-(4-chloro-phenyl)-6H-thieno[2,3-c]pyridin-7-one trifluoroacetateHCID 68953753—
SolventAcetic AcidHCID 176—
Product2-(4-chloro-phenyl)-6-[3-methoxy-4-(1-methyl-azetidin-3-yloxy)-phenyl]-6H-thieno[2,3-c]pyridin-7-oneHCID 2480358261.2%

Reaction Steps

Mix 6-[4-(azetidin-3-yloxy)-3-methoxy-phenyl]-2-(4-chloro-phenyl)-6H-thieno[2,3-c]pyridin-7-one trifluoroacetic acid salt (210 mg, 0.48 mmol) with methanol (10 mL) and acetic acid (0.3 mL). Add a solution of formaldehyde (0.20 mL, 2.66 mmol, 37% aqueous solution) and stir the mixture for 15 min. Add sodium cyanoborohydride (110 mg, 1.75 mmol) and stir the mixture at RT overnight. Concentrate the mixture in vacuo and partition the crude material between saturated NaHCO3 (25 mL) and CH2Cl2 (25 mL). Remove the organic solution and extract the aqueous phase with additional CH2Cl2 (2×25 mL). Combine the organic solutions and concentrate in vacuo. Purify the crude material by flash chromatography, using 5% MeOH (2N NH3) in CH2Cl2 as eluent, to give 133 mg (61%) of 2-(4-chloro-phenyl)-6-[3-methoxy-4-(1-methyl-azetidin-3-yloxy)-phenyl]-6H-thieno[2,3-c]pyridin-7-one as a white solid.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08263772B2
Source datasetuspto-grants-2012_09
ORD IDord-1c89662f58194acc80138f80fe983c9a
Source noteuspto-grants-2012_09