Sodium Iodide → Methyl 12-iodododecanoate

Participants

Reaction Steps

12-Bromododecanoic acid methyl ester (5.65 g, 19.3 mmol) was dissolved in acetone (50 ml). Sodium iodide (14.4 g, 96 mmol) was added and the reaction was refluxed under nitrogen for 20 h. The sample was concentrated under vacuum. Water (100 ml) was added, and the mixture was extracted with AcOEt (2×100 ml). The organic extracts were pooled and washed with water plus a small amount of sat. NaCl and sat. NaCl (100 ml each), dried over MgSO4, and concentrated to yield a light yellow oil (6.37 g, 97%).

Provenance & Evidence