HRID2402851

反应详情

EQUATION

反应方程式

HRID 2402851 的结构方程式

PROCEDURE

实验过程

In the same way as for the compound from Example 206, 58 mg (0.11 mmol) of [4-(4-chlorophenyl)-2-oxo-3-(3,3,3-trifluoro-2-hydroxypropyl)-2,3-dihydro-1H-imidazol-1-yl]acetic acid from Example 185A were reacted with 42 mg (0.12 mmol) of the compound from Example 180A. This gave 12 mg (18% of theory) of the target compound.