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HRID2411347

反应详情

EQUATION

反应方程式

HRID 2411347 的结构方程式

REACTANTS

反应物

2
结构：CI
HCID6328

Methyl iodide

CH3I

结构：CC(C)C1NC(=O)NC1=O
HCID103033

5-(1-Methylethyl)-2,4-imidazolidinedione

C6H10N2O2

PRODUCTS

生成物

1
结构：CC(C)C1NC(=O)N(C)C1=O
HCID53425842

3-Methyl-5-(propan-2-yl)imidazolidine-2,4-dione

C7H12N2O2

PROCEDURE

实验过程

Using 5-isopropylimidazolidine-2,4-dione (1.00 g) and methyl iodide (0.46 mL) and by the reaction and treatment in the same manner as in Preparation Example 214, the title compound (0.88 g) was obtained.

WORKUP

后处理

  1. customby the reaction and treatment in the same manner
  2. customas in Preparation Example 214