Styrene → HCID 73990325, compound

HRID 2416403Notes

Reaction equation

HRID 2416403 reaction equation
[Si:1]([C:23]1(Br)[CH:28]=[CH:27][CH:26]=[CH:25][CH:24]=1)([C:16]1(Br)[CH:21]=[CH:20][CH:19]=[CH:18][CH:17]=1)([C:9]1(Br)[CH:14]=[CH:13][CH:12]=[CH:11][CH:10]=1)[C:2]1(Br)[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.[CH2:30]=[CH:31][C:32]1[CH:37]=[CH:36][CH:35]=[CH:34][CH:33]=1>>[C:3]1([CH:30]=[CH:31][C:32]2[CH:37]=[CH:36][CH:35]=[CH:34][CH:33]=2)[CH:4]=[CH:5][CH:6]=[CH:7][C:2]=1[Si:1]([C:23]1[CH:28]=[CH:27][CH:26]=[CH:25][C:24]=1[CH:30]=[CH:31][C:32]1[CH:37]=[CH:36][CH:35]=[CH:34][CH:33]=1)([C:16]1[CH:21]=[CH:20][CH:19]=[CH:18][C:17]=1[CH:30]=[CH:31][C:32]1[CH:37]=[CH:36][CH:35]=[CH:34][CH:33]=1)[C:9]1[CH:14]=[CH:13][CH:12]=[CH:11][C:10]=1[CH:30]=[CH:31][C:32]1[CH:37]=[CH:36][CH:35]=[CH:34][CH:33]=1

Participants

3

Procedure

Use of tetrakis(4-bromophenyl)silane (Si(C6H4Br)4) gives access to structural analogs containing a silicon atom at the tetrahedral junction. Thus, reaction of Si(C6H4Br)4 with excess styrene gives tetrastilbenylsilane (Si(STB)4) in 52% yield using Pd(OAc)2 under phase transfer conditions. Similarly, (Si(C6H4Br)4) and 4,4′-tert-butylvinylstilbene yields tetrakis(4-tert-butylstyrylstilbenyl)silane (Si(tBuSSB)4) in 40% yield.

Workup

  1. additioncontaining a silicon atom at the tetrahedral junction

Sources & evidence

ORD record
ord-3b433d4d8ff0483ab52a30c5e671a429
Source dataset
uspto-grants-2004_11
Patent number
US06824890B2

Reaction notes

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